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The angle of depression of a point situated at a distance of $70m$ from the base of a tower is $60^\circ$. The height of the tower is:

A) $35\sqrt{3}m$
B) $70\sqrt{3}m$
C) $70m$
D) $70/3m$

Correct Answer: B) $70\sqrt{3}m$

1. **Identify Variables:** Height ($ = Opposite side), Distance ( = 70m$ = Adjacent side), Angle of Elevation = $60^\circ$ (same as angle of depression). 2. **Apply Tangent Ratio:** $$ an( heta) = rac{h}{d}$$ 3. **Substitute and Solve:** $$ an(60^\circ) = rac{h}{70}$$ $$\sqrt{3} = rac{h}{70}$$ $ = 70\sqrt{3} ext{ meters}$$

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