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Convert to **Radical Form** ^{2/5} y^{4/5}$ is:

A) $\sqrt[5]{xy^{2}}$
B) $\sqrt{x^{2}y^{4}}$
C) $\sqrt[5]{x^{2}y^{4}}$
D) $\sqrt[5]{x^{4}y^{2}}$

Correct Answer: C) $\sqrt[5]{x^{2}y^{4}}$

Using the rule ^{m/n} = \sqrt[n]{a^m}$: $^{2/5} y^{4/5} = (x^2 y^4)^{1/5} = \sqrt[5]{x^{2}y^{4}}$$

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